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10x^2+6x-1368=0
a = 10; b = 6; c = -1368;
Δ = b2-4ac
Δ = 62-4·10·(-1368)
Δ = 54756
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{54756}=234$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-234}{2*10}=\frac{-240}{20} =-12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+234}{2*10}=\frac{228}{20} =11+2/5 $
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